names = ["AA","BB","CC","DD","DD","FF"]print(names[1]) #取值print(names[0:4]) #切片print(names[-2:])#以坐标的方式取值，左闭右开，不写默认正/负无穷names.append("EE")#在最后追加字符串names.insert(2,"FF")#在计算机下标为2 的位置前面加字符串names.remove("FF")#移除第一个字符串del  names[0]#移除字符串names.pop()#默认删除最后一个字符串，可以加计算机下标print(names.index("DD"))获取第一个字符串的计算机位置print(names)print(names.count("DD"))#获取该字符串的数量#names.clear()#清除数组names.reverse()#倒置数组print(names)

 

#Author:Wuycgoods = (["苹果笔记本电脑",4200,4200111],         ["华为手机",2199],         ["字领露肩蓝色蕾丝",388.00],         ["Bettychow女装",328.00],         ["HP 笔记本",3900],         ["F七匹狼夹克外套",459.00 ],)'''for name,money in enumerate(goods):    print(name,money);#把下标取出来'''BuyGoods = [];i = 0for item in goods:    i = i + 1    print(str(i) + ":" , item[0],item[1])salary = int(input("工资："));print("输入 T 退出 ！")print("输入 P 打印商品！")while True:    input1 = input("商品编号：");    if (input1 == "T"):        print("--------Goods List-------")        for item in BuyGoods:            print(item)            # break;            exit()    elif (input1 == "P"):        for item in BuyGoods:            print(item)    if input1.isdigit():        good_num = int(input1)        if good_num > len(goods):            print("没有这个商品")        else:            good_money = goods[good_num-1][1]            if salary >= good_money:                BuyGoods.append(goods[good_num-1])                salary = salary - good_money                print("买了个 {goodname}，花了 {goodmoney}是，余额为：\033[31;1m{YE}\033[0m 元".format(goodname=goods[good_num-1][0],goodmoney=goods[good_num-1][1],YE=salary))            else:                print("\033[41;1m余额不足,重新选择！\033[0m")